#2275 closed defect (fixed)
Error when launching command from start menu in Python3
Reported by: | Mark Harkin | Owned by: | Antoine Martin |
---|---|---|---|
Priority: | major | Milestone: | 3.0 |
Component: | client | Version: | 2.5.x |
Keywords: | Cc: |
Description (last modified by )
Was just testing out Xpra on Python3 with latest beta and got the following when trying to open an application through the tray start menu.
Traceback (most recent call last): File "/usr/lib64/python3.7/site-packages/xpra/client/gtk_base/gtk_tray_menu_base.py", line 1657, in app_launch command = re.sub(r'\%[fFuU]', '', command) File "/usr/lib64/python3.7/re.py", line 192, in sub return _compile(pattern, flags).sub(repl, string, count) TypeError: cannot use a string pattern on a bytes-like object
Change History (2)
comment:1 Changed 2 years ago by
Description: | modified (diff) |
---|---|
Resolution: | → fixed |
Status: | new → closed |
comment:2 Changed 3 months ago by
this ticket has been moved to: https://github.com/Xpra-org/xpra/issues/2275
Note: See
TracTickets for help on using
tickets.
Fixed in r22446.