Xpra: Ticket #2275: Error when launching command from start menu in Python3

Was just testing out Xpra on Python3 with latest beta and got the following when trying to open an application through the tray start menu.

Traceback (most recent call last):
  File "/usr/lib64/python3.7/site-packages/xpra/client/gtk_base/gtk_tray_menu_base.py", line 1657, in app_launch
    command = re.sub(r'\%[fFuU]', '', command)
  File "/usr/lib64/python3.7/re.py", line 192, in sub
    return _compile(pattern, flags).sub(repl, string, count)
TypeError: cannot use a string pattern on a bytes-like object


Wed, 17 Apr 2019 11:59:01 GMT - Antoine Martin: status, description changed; resolution set

Fixed in r22446.


Sat, 23 Jan 2021 05:46:51 GMT - migration script:

this ticket has been moved to: https://github.com/Xpra-org/xpra/issues/2275